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If α and β are the distinct roots of the equation x^2+(3)^ 1 4x+3^ 1 2=0, then the value of α ^96(α ^12-1)+β ^96(β ^12-1) is equal to:

JEE Main 2021 — Mathematics Algebra

2021mcqhard

If α\alphaα and β\betaβ are the distinct roots of the equation x2+(3)14x+312=0{x}^{2}+{(3)}^{\frac{1}{4}}x+{3}^{\frac{1}{2}}=0x2+(3)41​x+321​=0, then the value of α96(α12−1)+β96(β12−1){\alpha }^{96}({\alpha }^{12}-1)+{\beta }^{96}({\beta }^{12}-1)α96(α12−1)+β96(β12−1) is equal to:

Official previous-year question

Held on 20 Jul 2021 · Verified 6 Jul 2026.

Options

  1. A

    56×32556\times {3}^{25}56×325

  2. B

    56×32456\times {3}^{24}56×324

  3. C

    52×32452\times {3}^{24}52×324

  4. D

    28×32528\times {3}^{25}28×325

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