D=∣110−2−1k0k4∣=4−k2
so, A is correct and B,C,E are incorrect. If k=±2
D1=∣1−26−2−12024∣=−48=0
So, no solution if k=±2
For the system of linear equations:
x−2y=1,x−y+kz=−2,ky+4z=6,k∈R
Consider the following statements:
(A) The system has unique solution if k=2,k=−2.
(B) The system has unique solution if k=−2.
(C) The system has unique solution if k=2.
(D) The system has no-solution if k=2.
(E) The system has infinite number of solutions if k=−2.
Which of the following statements are correct?
Held on 24 Feb 2021 · Verified 6 Jul 2026.
(A) and (E) only
(B) and (E) only
(A) and (D) only
(C) and (D) only
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