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The sum Σ _k=1^20(1+2+3+… +k) is .

JEE Main 2020 — Mathematics Algebra

2020integermedium

The sum ∑k=120(1+2+3+…+k)\displaystyle \sum _{k=1}^{20}(1+2+3+\ldots +k)k=1∑20​(1+2+3+…+k) is ___________.

Official previous-year question

Held on 8 Jan 2020 · Verified 6 Jul 2026.

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