Skip to main content

The product 2^ 1 4· 4^ 1 16· 8^ 1 48· 16^ 1 128· .... to ∞ is equal to:

JEE Main 2020 — Mathematics Algebra

2020mcqeasy

The product 214⋅4116⋅8148⋅161128⋅....{2}^{\frac{1}{4}}\cdot {4}^{\frac{1}{16}}\cdot {8}^{\frac{1}{48}}\cdot {16}^{\frac{1}{128}}\cdot ....241​⋅4161​⋅8481​⋅161281​⋅.... to ∞\infty∞ is equal to:

Official previous-year question

Held on 9 Jan 2020 · Verified 6 Jul 2026.

Options

  1. A

    212{2}^{\frac{1}{2}}221​

  2. B

    214{2}^{\frac{1}{4}}241​

  3. C

    111

  4. D

    222

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Algebra in other years

More JEE Main Algebra questions

Other Mathematics topics for JEE Main

Keep practicing Algebra

Work through every JEE Main Algebra PYQ, year by year.

Browse all Mathematics topics