EXAMINATION
2N,2A,2I,E,X,M,T,O
Case I: All are different, so 8P4=4!8!=8⋅7⋅6⋅5=1680
Case II: 2 same and 2 different, so 3C1C272!4!=3⋅21⋅12=756
Case III: 2 same and 2 same, so 3C22!2!4!=3⋅6=18
Total number of words=1680+756+18=2454
The number of 4 letter words (with or without meaning) that can be formed from the eleven letters of the word EXAMINATION is
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