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Let a_n be the n^th term of a G.P. of positive terms. If Σ _n=1^100 a_2n+1=200 and Σ _n=1^100 a_2n=100, then Σ _n=1^200 a_n is equal to:

JEE Main 2020 — Mathematics Algebra

2020mcqmedium

Let an{a}_{n}an​ be the nth{n}^{th}nth term of a G.P. of positive terms. If ∑n=1100a2n+1=200\displaystyle \sum _{n=1}^{100}{a}_{2n+1}=200n=1∑100​a2n+1​=200 and ∑n=1100a2n=100,\displaystyle \sum _{n=1}^{100}{a}_{2n}=100,n=1∑100​a2n​=100, then ∑n=1200an\displaystyle \sum _{n=1}^{200}{a}_{n}n=1∑200​an​ is equal to:

Official previous-year question

Held on 9 Jan 2020 · Verified 6 Jul 2026.

Options

  1. A

    300300300

  2. B

    225225225

  3. C

    175175175

  4. D

    150150150

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