Given, ∣z−i∣=∣z+2i∣
⇒x2+(y−1)2=x2+(y+2)2
⇒−2y+1=4y+4
⇒6y=−3⇒y=−21
From, ∣z∣=25, we get,
x2+y2=425⇒x2=424=6⇒z=±6−2i
Hence, ∣z+3i∣=6+425=449
∣z+3i∣=27
JEE Main 2020 — Mathematics Algebra
Let z be a complex number such that ∣z+2iz−i∣=1 and ∣z∣=25 . Then, the value of ∣z+3i∣ is
Held on 9 Jan 2020 · Verified 6 Jul 2026.
10
27
415
23
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