If α,β are roots of quadratic equation 5x2+6x−2=0
⇒5α2+6α−2=0⇒5α2+6α=2
⇒5β2+6β−2=0⇒5β2+6β=2
5S6+6S5=5(α6+β6)+6(α5+β5)
=α4(5α2+6α)+β4(5β2+6β)
=2(α4+β4)=2S4
JEE Main 2020 — Mathematics Algebra
Let α and β be the roots of the equation, 5x2+6x−2=0. If Sn=αn+βn,n=1,2,3,...., then
Held on 2 Sept 2020 · Verified 6 Jul 2026.
6S6+5S5=2S4
5S6+6S5+2S4=0
5S6+6S5=2S4
6S6+5S5+2S4=0
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