Tr+1=Cr16(cosθx)16−r(xsinθ1)r
for r=8 term is free from ′x′
T9=C816sin8θcos8θ1
T9=C816(sin2θ)828
In θ∈[8π,4π],l1=C81628 (∵ Minimum value of l1 at θ=4π)
In θ∈[16π,8π],l2=C816(21)828=C816⋅28⋅24 (∵Minimum value of l2 at θ=8π)
l1l2=C816.28C816.2824=16