Δ=∣x−22x−33x−52x−33x−45x−83x−44x−510x−17∣
Applying R2→R2−R1, R3→R3−R2, we get
Δ=∣x−2x−1x−22x−3x−12(x−2)3x−4x−16(x−2)∣=(x−1)(x−2)∣x−2112x−3123x−416∣
=−3x3+12x2−15x+6
∴B+C=12−15=−3
JEE Main 2020 — Mathematics Algebra
If Δ=∣x−22x−33x−52x−33x−45x−83x−44x−510x−17∣=Ax3+Bx2+Cx+D, then B+C is equal to :
Held on 3 Sept 2020 · Verified 6 Jul 2026.
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