S=1+r=1∑101−(2r)2(2r−1)
=1+10−r=1∑10(8r3−4r2)
=11−[8(210×11)2−4(610×11×21)]
=11−[2(110)2−140×11]
=11−22(1100−70)
=11−220(110−7)
∴ α−220β=11−220(103)
∴ α=11,β=103
(α,β)=(11,103).
If 1+(1−22⋅1)+(1−42⋅3)+(1−62⋅5)+……+(1−202⋅19)=α−220β, then an ordered pair (α,β) is equal to:
Held on 4 Sept 2020 · Verified 6 Jul 2026.
(10,97)
(11,103)
(10,103)
(11,97)
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