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If the system of equations x+y+z=2 2x+4y-z=6 3x+2y+λ z=μ has infinitely many solutions, then :

JEE Main 2020 — Mathematics Algebra

2020mcqeasy

If the system of equations

x+y+z=2x+y+z=2x+y+z=2

2x+4y−z=62x+4y-z=62x+4y−z=6

3x+2y+λz=μ3x+2y+\lambda z=\mu3x+2y+λz=μ

has infinitely many solutions, then :

Official previous-year question

Held on 4 Sept 2020 · Verified 6 Jul 2026.

Options

  1. A

    λ+2μ=14\lambda +2\mu =14λ+2μ=14

  2. B

    2λ−μ=52\lambda -\mu =52λ−μ=5

  3. C

    λ−2μ=−5\lambda -2\mu =-5λ−2μ=−5

  4. D

    2λ+μ=142\lambda +\mu =142λ+μ=14

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