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If the sum of the coefficients of all even powers of x in the product (1+x+x^2+… +x^2n)(1-x+x^2-x^3+… +x^2n) is 61, then n is equal to

JEE Main 2020 — Mathematics Algebra

2020integerhard

If the sum of the coefficients of all even powers of xxx in the product (1+x+x2+…+x2n)(1−x+x2−x3+…+x2n)(1+x+{x}^{2}+\ldots +{x}^{2n})(1-x+{x}^{2}-{x}^{3}+\ldots +{x}^{2n})(1+x+x2+…+x2n)(1−x+x2−x3+…+x2n) is 61,61,61, then n is equal to

Official previous-year question

Held on 7 Jan 2020 · Verified 6 Jul 2026.

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