∣1241bb21cc2∣→C2→C2−C1,C3→C3−C1∣1240b−2b2−40c−2c2−4∣=(b−2)(c−2)(c−b)
Let common difference of AP=d
∴b=2+d,c=2+2d
∣A∣=d×2d×d=2d3∈[2,16]
⇒d3∈[1,8]⇒d∈[1,2]⇒2d∈[2,4]
⇒2+2d∈[4,6]
∴c∈[4,6]
JEE Main 2019 — Mathematics Algebra
Let the numbers 2,b,c be in an A.P. and A=[1241bb21cc2] . If det(A)∈[2,16], then c lies in the interval:
Held on 8 Apr 2019 · Verified 6 Jul 2026.
[2,3)
[4,6]
[3,2+243]
(2+243,4)
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