Let α=23+2i, then z=α5+(αˉ)5
We know zˉn=zˉn,
then, z=2Re(α5)
Hence, I(z)=0.
JEE Main 2019 — Mathematics Algebra
Let z=(23+2i)5+(23−2i)5. If R(z) and I(z) respectively denote the real and imaginary parts of z, then
Held on 10 Jan 2019 · Verified 6 Jul 2026.
I(z)=0
R(z)<0 and I(z)>0
R(z)>0 and I(z)>0
R(z)=−3
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