Given 2(x+2)(x−2)(x−3)=1=20⇒x=−2,2,3.
∴n(A)=3
Again, −3<2x−1<9⇒−1<x<5
⇒x=0,1,2,3,4
∴n(B)=5
∴n(A×B)=3×5=15
∴Number of subset of A×B=215
Let Z be the set of integers. If A=x∈Z:2(x+2)(x2−5x+6)=1 and B=x∈Z:−3<2x−1<9, then the number of subsets of the set A×B, is :
Held on 12 Jan 2019 · Verified 6 Jul 2026.
212
210
218
215
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