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Let z_0 be a root of quadratic equation, x^2+x+1=0. If z=3+6iz_0^81-3iz_0^93 , then arg (z) is equal to:

JEE Main 2019 — Mathematics Algebra

2019mcqmedium

Let z0{z}_{0}z0​ be a root of quadratic equation, x2+x+1=0.{x}^{2}+x+1=0.x2+x+1=0. If z=3+6iz081−3iz093z=3+6i{z}_{0}^{81}-3i{z}_{0}^{93}z=3+6iz081​−3iz093​ , then argargarg (z)(z)(z) is equal to:

Official previous-year question

Held on 9 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    000

  2. B

    π4\frac{\pi }{4}4π​

  3. C

    π6\frac{\pi }{6}6π​

  4. D

    π3\frac{\pi }{3}3π​

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