Let the first terms of A.P. be A and common difference be d, then
a=A+6d
b=A+10d
c=A+12d
Given a,b,c are in G. P. ⇒b2=ac
⇒(A+10d)2=(A+6d)(A+12d)
⇒A2+100d2+20Ad=A2+18Ad+72d2
⇒A=−14d
Now ca=A+12dA+6d=−14d+12d−14d+6d=−2d−8d=4
JEE Main 2019 — Mathematics Algebra
Let a,b and c be the 7th,11th and 13th terms respectively of a non-constant A.P. . If these are also the three consecutive terms of a G.P. , then ca is equal to:
Held on 9 Jan 2019 · Verified 6 Jul 2026.
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