Let α and β are the roots of given equation 3m2x2+m(m−4)x+2=0.
\therefore \alpha +\beta =-\frac{m(m-4)}{3{m}^{2}}&\alpha \beta =\frac{2}{3{m}^{2}}.........(i)
Given \frac{\alpha }{\beta }=\lambda &\lambda +\frac{1}{\lambda }=1
⇒βα+αβ=1
⇒(α+β)2=3αβ
Using equation (i), we get
(3m2−m(m−4))2=3m23×2
⇒m=4±32
Hence, the least value of m is 4−32.