Let first term and common difference of AP be a and d respectively, then tn=a+(n−1)d ∴t19=a+18d=0 ∴a=−18d ∴t29t49=a+28da+48d =−18d+28d−18d+48d=10d30d=3 t49:t29=3:1
If 19 th term of a non-zero A.P. is zero, then its (49th term): (29th term) is:
JEE Main 2019 — Mathematics Algebra
If 19 th term of a non-zero A.P. is zero, then its (49th term): (29th term) is:
Held on 11 Jan 2019 · Verified 6 Jul 2026.
Options
- A
4: 1
- B
1: 3
- C
3: 1
- D
2: 1
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