\begin{matrix}7B \\ 5G\end{matrix}}\rightarrow (\begin{matrix}3B \\ 2G\end{matrix})
Total number of ways of forming a team of 3 boys and 2 girls =7C3×5C2=1.2.37.6.5×1.25.4=350
Total number of ways of forming a team if two specific boys B1,B2 always join the team
=5C1×5C2=50
So, the total number of ways of forming a team so that two specific boys never come together
=350−50=300