| (5) | (n) |
| Boys | Girls |
| 2 | 1 |
| 1 | 2 |
=5C2×nC1+5C1×nC2=1750
⇒10n+52n(n−1)=1750
⇒n2+3n−700=0
⇒n=−28,25
n cannot be negative
Hence n=25
JEE Main 2019 — Mathematics Algebra
A group of students comprises of 5 boys and n girls. If the number of ways, in which a team of 3 students can randomly be selected from this group such that there is at least one boy and at least one girl in each team, is 1750, then n is equal to
Held on 12 Apr 2019 · Verified 6 Jul 2026.
24
27
25
28
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