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Let 1 x_1, 1 x_2,… , 1 x_n(x_i≠ 0 for i=1,2,… .,n) be in A.P. such that x_1=4 and x_21=20. If n is the least positive integer for which x_n>50, then…

JEE Main 2018 — Mathematics Algebra

2018mcqhard

Let 1x1,1x2,…,1xn(xi≠0\frac{1}{{x}_{1}},\frac{1}{{x}_{2}},\ldots ,\frac{1}{{x}_{n}}({x}_{i}\neq 0x1​1​,x2​1​,…,xn​1​(xi​=0 for i=1,2,….,n)i=1,2,\ldots .,n)i=1,2,….,n) be in A.P. such that x1=4{x}_{1}=4x1​=4 and x21=20{x}_{21}=20x21​=20... If nnn is the least positive integer for which xn>50{x}_{n}>50xn​>50, then ∑i=1n(1xi)\displaystyle \sum _{i=1}^{n}(\frac{1}{{x}_{i}})i=1∑n​(xi​1​) is equal to

Official previous-year question

Held on 16 Apr 2018 · Verified 6 Jul 2026.

Options

  1. A

    333

  2. B

    18\frac{1}{8}81​

  3. C

    134\frac{13}{4}413​

  4. D

    138\frac{13}{8}813​

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