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Let f: A → B be a function defined as f(x)= x-1 x-2, where A=R-2 and B=R-1. Then f is

JEE Main 2018 — Mathematics Algebra

2018mcqmedium

Let f:A→f: \mathrm{A} \rightarrowf:A→ B be a function defined as f(x)=f(x)=f(x)= x−1x−2\frac{x-1}{x-2}x−2x−1​, where A=R−{2}A=R-\{2\}A=R−{2} and B=R−{1}B=R-\{1\}B=R−{1}. Then fff is

Official previous-year question

Held on 15 Apr 2018 · Verified 6 Jul 2026.

Options

  1. A

    invertible and f−1(y)=2y+1y−1f^{-1}(y)=\frac{2 y+1}{y-1}f−1(y)=y−12y+1​

  2. B

    invertible and f−1(y)=3y−1y−1f^{-1}(y)=\frac{3 y-1}{y-1}f−1(y)=y−13y−1​

  3. C

    no invertible

  4. D

    invertible and f−1(y)=2y−1y−1f^{-1}(y)=\frac{2 y-1}{y-1}f−1(y)=y−12y−1​

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