Suppose y=f(x) ⇒y=x−2x−1⇒yx−2y=x−1⇒(y−1)x=2y−1⇒x=f−1(y)=y−12y−1 As the function is invertible on the given domain and its inverse can be obtained as above.
Let f: A → B be a function defined as f(x)= x-1 x-2, where A=R-2 and B=R-1. Then f is
JEE Main 2018 — Mathematics Algebra
Let f:A→ B be a function defined as f(x)= x−2x−1, where A=R−{2} and B=R−{1}. Then f is
Held on 15 Apr 2018 · Verified 6 Jul 2026.
Options
- A
invertible and f−1(y)=y−12y+1
- B
invertible and f−1(y)=y−13y−1
- C
no invertible
- D
invertible and f−1(y)=y−12y−1
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