[5x3+1−5x3−12]8+[5x3+1+5x3−12]8
Rationalizing denominators of both the brackets,
=[5x3+1+5x3−1]8+[5x3+1−5x3−1]8
=2[8C0(5x3+1)8+8C2(5x3+1)6(5x3−1)2+8C4(5x3+1)4(5x3−1)4+8C6(5x3+1)2(5x3−1)6+8C8(5x3−1)8]
=2[(5x3−1)4+28(5x3+1)3(5x3−1)+70(5x3+1)2(5x3−1)2+28(5x3+1)(5x3−1)3+(5x3+1)4]
So, n=12 and
m=2(54+140.53+70.54+140.53+54)=160000=(20)4