We have,
5cosA+3=0⇒cosA=−53
Clearly, A∈(90∘,180∘)
Now, roots of equation
9x2+27x+20=0
⇒x=18−27±729−720=18−27±3
⇒x=−35,−34
Then, −35=secA and −34=tanA.
Hence, the roots are secA and tanA.
If an angle A of a ΔABC satisfies 5cosA+3=0, then the roots of the quadratic equation 9x2+27x+20=0 are
Held on 16 Apr 2018 · Verified 6 Jul 2026.
secA,cotA
secA,tanA
tanA,cosA
sinA,secA
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