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If an angle A of a Δ ABC satisfies 5 cosA+3=0, then the roots of the quadratic equation 9x^2+27x+20=0 are

JEE Main 2018 — Mathematics Algebra

2018mcqmedium

If an angle AAA of a ΔABC\Delta ABCΔABC satisfies 5cosA+3=05\mathrm{cos}A+3=05cosA+3=0, then the roots of the quadratic equation 9x2+27x+20=09{x}^{2}+27x+20=09x2+27x+20=0 are

Official previous-year question

Held on 16 Apr 2018 · Verified 6 Jul 2026.

Options

  1. A

    secA,cotA\mathrm{sec}A,\mathrm{cot}AsecA,cotA

  2. B

    secA,tanA\mathrm{sec}A,\mathrm{tan}AsecA,tanA

  3. C

    tanA,cosA\mathrm{tan}A,\mathrm{cos}AtanA,cosA

  4. D

    sinA,secA\mathrm{sin}A,\mathrm{sec}AsinA,secA

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