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Let S_n= 1 1^3+ 1+2 1^3+2^3+ 1+2+3 1^3+2^3+3^3+… + 1+2+… ,+n 1^3+2^3+… n^3 . If 100 S_n=n, then n is equal to:

JEE Main 2017 — Mathematics Algebra

2017mcqhard

Let Sn=113+1+213+23+1+2+313+23+33+…+1+2+…,+n13+23+…n3{S}_{n}=\frac{1}{{1}^{3}}+\frac{1+2}{{1}^{3}+{2}^{3}}+\frac{1+2+3}{{1}^{3}+{2}^{3}+{3}^{3}}+\ldots +\frac{1+2+\ldots ,+n}{{1}^{3}+{2}^{3}+\ldots {n}^{3}}Sn​=131​+13+231+2​+13+23+331+2+3​+…+13+23+…n31+2+…,+n​ . If 100Sn=n,100 {S}_{n}=n,100Sn​=n, then nnn is equal to:

Official previous-year question

Held on 9 Apr 2017 · Verified 6 Jul 2026.

Options

  1. A

    200200200

  2. B

    199199199

  3. C

    999999

  4. D

    191919

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