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Let ω be a complex number such that 2ω +1=z where z=√-3 . If | … |=3k, Then k can be equal to:

JEE Main 2017 — Mathematics Algebra

2017mcqhard

Let ω\omegaω be a complex number such that 2ω+1=z2\omega +1=z2ω+1=z where z=−3z=\sqrt{-3}z=−3​ . If

∣1111−ω2−1ω21ω2ω7∣=3k,|\begin{matrix}1 & 1 & 1 \\ 1 & -{\omega }^{2}-1 & {\omega }^{2} \\ 1 & {\omega }^{2} & {\omega }^{7}\end{matrix}|=3k,∣111​1−ω2−1ω2​1ω2ω7​∣=3k,

Then kkk can be equal to:

Official previous-year question

Held on 2 Apr 2017 · Verified 6 Jul 2026.

Options

  1. A

    –z–z–z

  2. B

    1z\frac{1}{z}z1​

  3. C

    −1-1−1

  4. D

    111

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