f(x)+2.f(x1)=3x…(1)
Replace x by x1, we get
f(x1)+2f(x)=x3…(2)
From (1) and (2)
3f(x)=x6−3x
f(x)=x2−x
∵ f(x)=f(−x)
Therefore x2−x=−x2+x
⇒x4=2x
⇒2=x2
⇒x=±2
Contains exactly two elements
If f(x)+2f(x1)=3x,x=0, and S=x∈R:f(x)=f(−x), then S
Held on 3 Apr 2016 · Verified 6 Jul 2026.
Contains exactly two elements
Contains more than two elements
Is an empty set
Contains exactly one element
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