Given, α,β are roots of x2−6x−2=0.
⇒α2−6α−2=0 and β2−6β−2=0
⇒α2−2=6α andβ2−2=6β...(1)
2a9a10−2a8=2(α9−β9)(α10−β10)−2(α8−β8)
=2(α9−β9)(α10−2α8)−(β10−2β8)
=2(α9−β9)α8(α2−2)−β8(β2−2)
=2(α9−β9)α8(6α)−β8(6β) [∵ From (1)]
=2(α9−β9)6α9−6β9=3
JEE Main 2015 — Mathematics Algebra
Let α and β be the roots of equation x2−6x−2=0. If an=αn−βn,∀n≥1, then the value of 2a9a10−2a8 is equal to
Held on 4 Apr 2015 · Verified 6 Jul 2026.
−3
6
−6
3
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