Given, AAT=9I
[12a2122−2b][12221−2a2b]=9I
⇒[90a+4+2b092a+2−2ba+4+2b2a+2−2ba2+4+b2]=[900090009]
Equation a+4+2b=0⇒a+2b=−4...(1)
2a+2−2b=0⇒2a−2b=−2...(2)
& {a}^{2}+4+{b}^{2}=9\Rightarrow {a}^{2}+{b}^{2}=5...(3)
On solving, we get a=−2,b=−1
JEE Main 2015 — Mathematics Algebra
If A=[12a2122−2b] is a matrix satisfying the equation AAT=9I , where Iis 3×3 identity matrix, then the ordered pair (a,b) is equal to
Held on 4 Apr 2015 · Verified 6 Jul 2026.
(−2,−1)
(2,−1)
(−2,1)
(2,1)
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