Let the three numbers of the GP be a,ar and ar2 where r is the common ratio.
According to the given condition, a,2ar and ar2 are in AP.
∴2ar=2a+ar2
∴a+ar2=4ar
∴r2+1=4r
∴r2−4r+1=0
∴r=24±16−4
=24±23=2±3
As it is an 'increasing' GP, r>1.
∴r=2+3.
JEE Main 2014 — Mathematics Algebra
Three positive numbers form an increasing G.P. If the middle term in this G.P. is doubled, the new numbers are in A.P. Then the common ratio of the G.P. is :
Held on 6 Apr 2014 · Verified 6 Jul 2026.
2−3
2+3
2+3
3+2
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