x2+∣2x−3∣−4=0∣2x−3∣={(2x−3)−(2x−3) if if x>23x<23 for x>23,x2+2x−3−4=0x2+2x−7=0x=2−2±4+28=2−2±42=−1±22 Here x=22−1{22−1<23} for x<23x2−2x+3−4=0⇒x2−2x−1=0⇒x=22±4+4=22±22=1±2 Here x=1−2{(1−2)<23} Sum of roots: (22−1)+(1−2)=2
The sum of the roots of the equation, x^2+|2 x-3|-4=0, is:
JEE Main 2014 — Mathematics Algebra
The sum of the roots of the equation, x2+∣2x−3∣−4=0, is:
Held on 12 Apr 2014 · Verified 6 Jul 2026.
Options
- A
2
- B
−2
- C
2
- D
−2
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