Let rth and (r+1)th term has equal coefficient (2+3x)55=255(1+6x)55rth term =25555Cr(6x)r Coefficient of xr is 25555Cr6r1 (r+1)th term =25555Cr+1(6x)r+1 Coefficient of xr+1 is 25555Cr+1⋅6r+11 Both coefficients are equal 25555Cr6r1=25555Cr+16r+11 ∣r∣55−r1=⌊r+1∣54−r1⋅616(r+1)=55−r6r+6=55−r7r=49r=7(r+1)=8 Coefficient of 7th and 8th terms are equal.
If (2+ x 3 )^55 is expanded in the ascending powers of x and the coefficients of powers of x in two consecutive terms of the expansion are equal,…
JEE Main 2014 — Mathematics Algebra
If (2+3x)55 is expanded in the ascending powers of x and the coefficients of powers of x in two consecutive terms of the expansion are equal, then these terms are:
Held on 12 Apr 2014 · Verified 6 Jul 2026.
Options
- A
7th and 8th
- B
8th and 9th
- C
28th and 29th
- D
27th and 28th
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