f(x)=y=x2−x+5 x2−x+41−41+5=y(x−21)2+419=y(x−21)2=y−419x−21=±y−419 x=21±y−419 As x>21x=21+y−419g(x)=21+x−419g′(x)=2x−4191 g′(7)=27−4191=2228−191=31
JEE Main 2014 — Mathematics Algebra
If f(x)=x2−x+5,x>21, and g(x) is its inverse function, then g′(7) equals:
Held on 12 Apr 2014 · Verified 6 Jul 2026.
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