In 8 digits numbers, 4 places are odd places. Also, in the given 8 digits, there are three odd digits 1,1 and 3. No. of ways three odd digits arranged at four even places =2!4P3=2!4! No. of ways the remaining five digits 2 , 2, 2, 4 and 4 arranged at remaining five places =3!2!5! Hence, required number of 8 digits number =2!4!×3!2!5!=120
8-digit numbers are formed using the digits 1, 1, 2, 2,2,3,4,4. The number of such numbers in which the odd digits do no occupy odd places, is:
JEE Main 2014 — Mathematics Algebra
8-digit numbers are formed using the digits 1, 1, 2, 2,2,3,4,4. The number of such numbers in which the odd digits do no occupy odd places, is:
Held on 12 Apr 2014 · Verified 6 Jul 2026.
Options
- A
160
- B
120
- C
60
- D
48
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