We know, (x2/3−x1/3+1)(x1/3+1)=x+1
⇒x2/3−x1/3+1x+1=x1/3+1
Also, x−xx−1=x(x−1)(x−1)(x+1)=xx+1=1+x−1/2
Hence, the given binomial becomes (x1/3−x−1/2)10.
General term =10Cr(−1)rx310−rx−2r
Hence, for term independent of x.
We get 310−r=2r
20−2r=3r
r=4
∴ Term Independent of x=10C4=210