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The least integral value α of x such that x-5 x^2+5 x-14>0, satisfies :

JEE Main 2013 — Mathematics Algebra

2013mcqeasy

The least integral value α\alphaα of xxx such that x−5x2+5x−14>0\frac{x-5}{x^2+5 x-14}>0x2+5x−14x−5​>0, satisfies :

Official previous-year question

Held on 23 Apr 2013 · Verified 6 Jul 2026.

Options

  1. A

    α2+3α−4=0\alpha^2+3 \alpha-4=0α2+3α−4=0

  2. B

    α2−5α+4=0\alpha^2-5 \alpha+4=0α2−5α+4=0

  3. C

    α2−7α+6=0\alpha^2-7 \alpha+6=0α2−7α+6=0

  4. D

    α2+5α−6=0\alpha^2+5 \alpha-6=0α2+5α−6=0

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