Given [pqr]332420132=[301]⇒[3p+3q+2r4p+2qp+3q+2r]=[301]⇒3p+3q+2r=34p+2q=0⇒q=−2pp+3q+2r=1 p=1,q=−2,r=3 ∴2p+q−r=2(1)+(−2)−(3)=−3.
If p,q,r are 3 real numbers satisfying the matrix equation, [pqr]332420132=[301] then 2p+q−r equals :
Held on 22 Apr 2013 · Verified 6 Jul 2026.
−3
−1
4
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