Let z1=1+i and z2=1−i z1z2=1+i1−i=(1+i)(1−i)(1−i)(1−i)=−i 2z1−3z22z1+3z2=2−3(z1z2)2+3(z1z2)=2+3i2−3i 2z1−3z22z1+3z2=2+3i2−3i=2+3i2−3i [∵z2z1=∣z2∣∣z1∣] =4+94+9=1
If Z_1 ≠ 0 and Z_2 be two complex numbers such that Z_2 Z_1 is a purely imaginary number, then | 2 Z_1+3 Z_2 2 Z_1-3 Z_2 | is equal to:
JEE Main 2013 — Mathematics Algebra
If Z1=0 and Z2 be two complex numbers such that Z1Z2 is a purely imaginary number, then 2Z1−3Z22Z1+3Z2 is equal to:
Held on 9 Apr 2013 · Verified 6 Jul 2026.
Options
- A
2
- B
5
- C
3
- D
1
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