Given α3+β3=−p and αβ=q Let βα2 and αβ2 be the root of required quadratic equation. So, βα2+αβ2=αβα3+β3=q−p and βα2×αβ2=αβ=q Hence, required quadratic equation is x2−(q−p)x+q=0⇒x2+qpx+q=0⇒qx2+px+q2=0
If p and q are non-zero real numbers and α^3+β^3=-p, α β=q, then a quadratic equation whose roots are α^2 β, β^2 α is :
JEE Main 2013 — Mathematics Algebra
If p and q are non-zero real numbers and α3+β3=−p,αβ=q, then a quadratic equation whose roots are βα2,αβ2 is :
Held on 25 Apr 2013 · Verified 6 Jul 2026.
Options
- A
px2−qx+p2=0
- B
qx2+px+q2=0
- C
px2+qx+p2=0
- D
qx2−px+q2=0
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