There are 2 vowels and 4 consonants in the letters a,b,c,d,e,f. If we select one vowel, then number of arrangements =2C1×4C2×3!=2×24×3×3×2=72 If we select two vowels, then number of arrangements =2C2×4C1×3!=1×4×6=24 Hence, total number of arrangements =72+24=96
The number of arrangements that can be formed from the letters a, b, c, d, e, f taken 3 at a time without repetition and each arrangement containing…
JEE Main 2012 — Mathematics Algebra
The number of arrangements that can be formed from the letters a,b,c,d,e,f taken 3 at a time without repetition and each arrangement containing at least one vowel, is
Held on 19 May 2012 · Verified 6 Jul 2026.
Options
- A
96
- B
128
- C
24
- D
72
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