Given quadratic equation is px2+qx+r=0D=q2−4pr Since α and β are two complex root ∴β=αˉ⇒∣β∣=∣αˉ∣⇒∣β∣=∣α∣(∵∣αˉ∣=∣α∣) Consider ∣α∣+∣β∣=∣α∣+∣α∣=2∣α∣>2.1=2(∵∣β∣=∣α∣)(∵∣α∣>1) Hence, ∣α∣+∣β∣ is greater than 2 .
JEE Main 2012 — Mathematics Algebra
Let p,q,r∈R and r>p>0. If the quadratic equation px2+qx+r=0 has two complex roots α and β, then ∣α∣+∣β∣ is
Held on 19 May 2012 · Verified 6 Jul 2026.
equal to 1
less than 2 but not equal to 1
greater than 2
equal to 2
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