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Let X and Y are two events such that P(X ∪ Y=) P X ∩(Y . ) Statement 1: P (X ∩ Y^prime=dotP X^prime ∩(Y=0 ) . Statement 2: P(X) P Y ∈ 2) P X ∩ Y( )

JEE Main 2012 — Mathematics Algebra

2012mcqmedium

Let XXX and YYY are two events such that P(X∪Y=)PX∩(Y.)P(X \cup Y=) P X \cap(Y . \quad)P(X∪Y=)PX∩(Y.) Statement 1: P(X∩Y′=P˙X′∩(Y=0)P\left(X \cap Y^{\prime}=\dot{P} X^{\prime} \cap(Y=0 \quad)\right.P(X∩Y′=P˙X′∩(Y=0) Statement 2: P(X)PY∈2)PX∩Y()P(X) P Y \in 2) P X \cap Y(\quad)P(X)PY∈2)PX∩Y()

Official previous-year question

Held on 7 May 2012 · Verified 6 Jul 2026.

Options

  1. A

    Statement 1 is false, Statement 2 is true.

  2. B

    Statement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation of Statement 1.

  3. C

    Statement 1 is true, Statement 2 is false.

  4. D

    Statement 1 is true, Statement 2 is true; Statement 2 is a correct explanation of Statement 1.

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