Let X and Y be two events such that P(X∪Y)=P(X∩Y) We know P(X∪Y)=P(X)+P(Y)−P(X∩Y)P(X∩Y)=P(X)+P(Y)−P(X∩Y) (from (1)⇒P(X)+P(Y)=2P(X∩Y) Hence, Statement −2 is true. Now, P(X∩Y′)=P(X)−P(X∩Y) and P(X′∩Y)=P(Y)−P(X∩Y) This implies statement-1 is also true.