Let g(x)=3ax3+b⋅2x2+cx g′(x)=ax2+bx+c Given: ax2+bx+c=0 and 2a+3b+6c=0 Statement-2: (i) g(0)=0 and g(1) =3a+2b+c=62a+3b+6c=60=0⇒g(0)=g(1) (ii) g is continuous on [0,1] and differentiable on (0,1) ∴ By Rolle's theorem ∃k∈(0,1) such that g′(k)=0 This holds the statement 2. Also, from statement-2, we can say ax2+bx+c=0 has at least one root in (0,1). Thus statement-1 and 2 both are true and statement-2 is a correct explanation for statement-1.
Consider a quadratic equation a x^2+b x+c=0, where 2 a+3 b+6 c=0 and let g(x)=a x^3 3+b x^2 2+c x. Statement 1: The quadratic equation has at least…
JEE Main 2012 — Mathematics Algebra
Consider a quadratic equation ax2+bx+c=0, where 2a+3b+6c=0 and let g(x)=a3x3+b2x2+cx. Statement 1: The quadratic equation has at least one root in the interval (0,1). Statement 2: The Rolle's theorem is applicable to function g(x) on the interval [0,1].
Held on 19 May 2012 · Verified 6 Jul 2026.
Options
- A
Statement 1 is false, Statement 2 is true.
- B
Statement 1 is true, Statement 2 is false.
- C
Statement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for Statement 1.
- D
Statement 1 is true, Statement 2 is true, , Statement 2 is a correct explanation for Statement 1.
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