a−bca+1b+1c−1a−1b−1c+1+(−1)na+1a−1ab+1b−1−bc−1c+1c=a−bca+1b+1c−1a−1b−1c+1+(−1)na+1b+1c−1a−1b−1c+1a−bc=a−bca+1b+1c−1a−1b−1c+1+(−1)n+1a+1b+1c−1a−bca−1b−1c+1=a−bca+1b+1c−1a−1b−1c+1+(−1)n+2a−bca+1b+1c−1a−1b−1c+1 This is equal to zero only if n+2 is odd i.e. n is odd integer.
Let a, b, c be such that b(a+c) ≠ 0. If | … |=0, then the value of ' n ' is
JEE Main 2009 — Mathematics Algebra
Let a,b,c be such that b(a+c)=0. If a−bca+1b+1c−1a−1b−1c+1+a+1a−1(−1)n+2ab+1b−1(−1)n+1bc−1c+1(−1)nc=0, then the value of ' n ' is
Held on 30 Apr 2009 · Verified 6 Jul 2026.
Options
- A
zero
- B
any even integer
- C
any odd integer
- D
any integer
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