bx2+cx+a=0 Roots are imaginary ⇒c2−4ab<0⇒c2<4ab⇒−c2>−4ab 3b2x2+6bcx+2c2 since 3b2>0 Given expression has minimum value Minimum value =4(3b2)4(3b2)(2c2)−36b2c2=−12b212b2c2=−c2>−4ab.
If the roots of the equation b x^2+c x+a=0 be imaginary, then for all real values of x, the expression 3 b^2 x^2+6 b c x+2 c^2 is
JEE Main 2009 — Mathematics Algebra
If the roots of the equation bx2+cx+a=0 be imaginary, then for all real values of x, the expression 3b2x2+6bcx+2c2 is
Held on 30 Apr 2009 · Verified 6 Jul 2026.
Options
- A
greater than 4ab
- B
less than 4ab
- C
greater than −4ab
- D
less than - 4ab
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Algebra in other years
More JEE Main Algebra questions
The number of elements in the set $S = \left\{(r, k) : k \in \mathbb{Z} \text{ and } {}^{36}C_{r+1} = \dfrac{6\left({}^{35}C_r\right)}{(k^2 - 3)}\right\}$, is :
Suppose $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are in A.P. and $\mathrm{a}^{2}, 2 \mathrm{~b}^{2}, \mathrm{c}^{2}$ are in G.P. If $\mathrm{a}<\mathrm{b}<\mathrm{c}$ and $\mathrm{a}+\mathrm{b}+\mathrm{c}=1$, then $9\left(\mathrm{a}^{2}+\mathrm{b}^{2}+\mathrm{c}^{2}\right)$ is equal to $\_\_\_\_$ .
Let $S=\left\{z \in \mathbb{C}: 4 z^{2}+\bar{z}=0\right\}$. Then $\sum_{z \in S}|z|^{2}$ is equal to:
Let $S=\{z: 3 \leqslant|2 z-3(1+i)| \leqslant 7\}$ be a set of complex numbers. Then $\min _{z \in S}\left|\left(z+\frac{1}{2}(5+3 i)\right)\right|$ is equal to :
Let $A = \begin{bmatrix} 1 & 0 & 0 \\ 3 & 1 & 0 \\ 9 & 3 & 1 \end{bmatrix}$ and $B = [b_{ij}]$, $1 \leq i, j \leq 3$. If $B = A^{99} - I$, then the value of $\dfrac{b_{31} - b_{21}}{b_{32}}$ is :
Other Mathematics topics for JEE Main
Keep practicing Algebra
Work through every JEE Main Algebra PYQ, year by year.