Let α and 4β be roots of x2−6x+a=0 and α,3β be the roots of x2−cx+6=0, then α+4β=6 and 4αβ=a α+3β=c and 3αβ=6. We get αβ=2⇒a=8 So the first equation is x2−6x+8=0⇒x=2,4 If α=2 and 4β=4 then 3β=3 If α=4 and 4β=2, then 3β=3/2 (non-integer) ∴ common root is x=2.
The quadratic equations x^2-6 x+a=0 and x^2-c x+6=0 have one root in common. The other roots of the first and second equations are integers in the…
JEE Main 2008 — Mathematics Algebra
The quadratic equations x2−6x+a=0 and x2−cx+6=0 have one root in common. The other roots of the first and second equations are integers in the ratio 4:3. Then the common root is
Held on 30 Apr 2008 · Verified 6 Jul 2026.
Options
- A
1
- B
4
- C
3
- D
2
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