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Let a_1, a_2, a_3, … be terms of an A.P. If a_1+a_2+… a_p a_1+a_2+…+a_q= p^2 q^2, p ≠ q, then a_6 a_21 equals

JEE Main 2006 — Mathematics Algebra

2006mcqeasy

Let a1,a2,a3,…a_1, a_2, a_3, \ldotsa1​,a2​,a3​,… be terms of an A.P. If a1+a2+⋯apa1+a2+⋯+aq=p2q2,p≠q\frac{a_1+a_2+\cdots a_p}{a_1+a_2+\cdots+a_q}=\frac{p^2}{q^2}, p \neq qa1​+a2​+⋯+aq​a1​+a2​+⋯ap​​=q2p2​,p=q, then a6a21\frac{a_6}{a_{21}}a21​a6​​ equals

Official previous-year question

Held on 30 Apr 2006 · Verified 6 Jul 2026.

Options

  1. A

    4111\frac{41}{11}1141​

  2. B

    72\frac{7}{2}27​

  3. C

    27\frac{2}{7}72​

  4. D

    1141\frac{11}{41}4111​

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