Given mC,mC,mCr+1 are in A.P. 2mCr=mCr−1+mCr+1⇒2=mCrmCr−1+mCrmCr+1=m−r+1r+r+1m−r⇒m2−m(4r+1)+4r2−2=0
If the coefficients of r th, (r+1) th and (r+2) th terms in the binomial expansion of (1+ y)^m are in A.P., then m and r satisfy the equation
JEE Main 2005 — Mathematics Algebra
If the coefficients of r th, (r+1) th and (r+2) th terms in the binomial expansion of (1+ y)m are in A.P., then m and r satisfy the equation
Held on 30 Apr 2005 · Verified 6 Jul 2026.
Options
- A
m2−m(4r−1)+4r2−2=0
- B
m2−m(4r+1)+4r2+2=0
- C
m2−m(4r+1)+4r2−2=0
- D
m2−m(4r−1)+4r2+2=0
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